Here is fully solved paper of TIFR GS 2010 with justification of each and every step, hope you'll enjoy it. For any query feel free to write at sushantkala786@gmail.com . PART - 'A' Q.1 Ans. (c). phi(60) = 16 Justification -: We know that in a cyclic group G of order n generated by a. The order of an element a^(k) is n/(n,k)=n iff (n,k)=1. So the number of generators of G are phi(n). Q.2 Ans. (a). (a) False, Consider the direct product Z_3*Z_3*Z_3. (b) True, Any Abelian group of order 14 must-have elements a and b with respective order 2 and 7 ( Cauchy Theorem ). Then a*b generates the group. (c) True, Same logic as in option (b). (d...
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